12x+2[6+7(x+1)]=0

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Solution for 12x+2[6+7(x+1)]=0 equation:


Simplifying
12x + 2[6 + 7(x + 1)] = 0

Reorder the terms:
12x + 2[6 + 7(1 + x)] = 0
12x + 2[6 + (1 * 7 + x * 7)] = 0
12x + 2[6 + (7 + 7x)] = 0

Combine like terms: 6 + 7 = 13
12x + 2[13 + 7x] = 0
12x + [13 * 2 + 7x * 2] = 0
12x + [26 + 14x] = 0

Reorder the terms:
26 + 12x + 14x = 0

Combine like terms: 12x + 14x = 26x
26 + 26x = 0

Solving
26 + 26x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-26' to each side of the equation.
26 + -26 + 26x = 0 + -26

Combine like terms: 26 + -26 = 0
0 + 26x = 0 + -26
26x = 0 + -26

Combine like terms: 0 + -26 = -26
26x = -26

Divide each side by '26'.
x = -1

Simplifying
x = -1

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